conducting wire

Question

A 0.504 m length of conducting wire carrying a current of 62.1 A is

Answer 1

Length of current carrying wire l = 0.504 m

Current through wire i = 62.1 A

Consider perpendicular external magnetic 
field with magnitude 0.203 T.[ Not given in problem , so we considered ]

External magnetic 
field is perpendicular θ = 90º

Magnetic 
field of magnitude B = 0.203 T.

The magnitude of the magnetic force on this wire is F = Bilsinθ

F = (0.203)(62.1)(0.504)sin(90) = 6.3536 N

The magnitude of the magnetic force on this wire is 6.3536 N.