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A 15-ft rope is cut into 3 parts. The length of one part is 2x the second.

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 the 3rd is 5 ft shorter than the longest. how long is each piece?

asked Nov 20, 2014 in ALGEBRA 1 by anonymous

1 Answer

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Length of rope = 15 ft.

The length of second part 2x ft.

So the first part length is x ft.

Longest piece of the rope is second part.

Third part length is 2x - 5.

(x) + (2x) + (2x - 5) = 15

x + 2x + 2x - 5 = 15

5x - 5 = 15

5(x - 1) = 15

x - 1 = 15/5

x - 1 = 3

x = 3 + 1

x = 4

first part of rope 4 ft

Second part of rope = 2(4) = 8ft

Third part of rope = 8 - 5 = 3 ft

Lengths of three pieces are 4ft, 8ft, 3ft.

answered Nov 20, 2014 by david Expert

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