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Question

A ball that is hit thrown horizontally with a velocity of V metres per second will travela distance metres before hitting the ground, where d=√h/4=g and h is the height, in metres from which the ball was hit or thrown. How far will a ball that is hit with a velocity of 45m/s at a height of 0.8m above the ground travel before hitting the ground to the nearest metres.

Comments

Please provide us the correct expression of d.

Answer 1

Distance Travelled by the ball before hitting the ground is d = (v√h)/4g

Where v is the velocity and h is the height of ball above the ground.

The Height above the ground is 0.8

Velocity of the ball is 45 m/sec

Distance travelled d = (v√h)/4g

d = (45*√0.8)/(2*9.8) = 2.0535

Therefore the distance travelled before hitting the ground is 2.0535 mts.