math help

Question

 

 

sorry for the graph :( 

 graph of the linear. draw an accurate graph of the reciprocal of this linear and write the equation

Answer 1

First we need to find the line equation.

Observe the graph,

The graph passes through the points (3,0) and (0,3).

Now slope of the function

m =(y₂ - y₁)/ (x₂ - x₁)

m = (3-0)/(0-3) = 3/(-3) = -1

m = -1

Slope - intercept form of line equation is y = mx + b.

y = -x+b

The point (3,0) passes through the line, the substitute x = 3 and y = 0.

0= -3+b

b = 3

Therefore the line equation is y = -x + 3.

 

Now reciprocal of the function is w = 1/(-x+3)

We can observe that the function is not defined at x = 3.

 

Graph

Plot the function.

Note: the dashed line indicates that the function is not defined at x = 3.

Therefore,

The tangent line is y = -x+3.

Reciprocal of the function is w = 1/(-x+3).