Welcome :: Homework Help and Answers :: Mathskey.com
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,459 questions

17,854 answers

1,446 comments

811,117 users

math help !!7

0 votes
A piece of wire 120 cm long is bent to form right triangle with hypotenuse of 51cm. What is the length each leg of the triangle. Write your own system of equation and show how to solve this problem algebraically using your equation.
asked Jan 19, 2015 in PRECALCULUS by anonymous

1 Answer

0 votes

Step 1:

Right angle triangle with hypotenuse of 51cm.

Let  image,image are the remaining two legs of right angled triangle.

Using Pythagoras theorem,

----->.equation(1)

Step 2:

Length of wire is 120 cm.

image

image

Step 3:

Substitute image value in equation(1).

image

Divide each side by 2.

image

Step 4:

Solve the equation by using factorization.

image

Apply zero product property.

image and image

image and image.

Step 5:

Substitute image value in .

image

Substitute image value in .

Solution:

The two legs of right angled triangle are 24 cm and 45 cm.

answered Jan 19, 2015 by Sammi Mentor
edited Jan 19, 2015 by Sammi

Related questions

asked Nov 5, 2014 in PRECALCULUS by anonymous
asked Jan 19, 2015 in PRECALCULUS by anonymous
asked Jan 19, 2015 in PRECALCULUS by anonymous
asked Jan 19, 2015 in PRECALCULUS by anonymous
asked Jan 19, 2015 in PRECALCULUS by anonymous
asked Dec 19, 2014 in PRECALCULUS by anonymous
asked Dec 19, 2014 in PRECALCULUS by anonymous
asked Dec 9, 2014 in PRECALCULUS by anonymous
asked Nov 15, 2014 in PRECALCULUS by anonymous
asked Nov 21, 2014 in PRECALCULUS by anonymous
asked Nov 21, 2014 in PRECALCULUS by anonymous
asked Nov 21, 2014 in PRECALCULUS by anonymous
asked Jan 19, 2015 in PRECALCULUS by anonymous
asked Jan 19, 2015 in PRECALCULUS by anonymous
asked Jan 19, 2015 in PRECALCULUS by anonymous
asked Dec 19, 2014 in PRECALCULUS by anonymous
asked Dec 19, 2014 in PRECALCULUS by anonymous
asked Dec 19, 2014 in PRECALCULUS by anonymous
asked Dec 9, 2014 in PRECALCULUS by anonymous
asked Dec 9, 2014 in PRECALCULUS by anonymous
...