Welcome :: Homework Help and Answers :: Mathskey.com
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,459 questions

17,854 answers

1,446 comments

811,139 users

help graph!

0 votes
Draw an accurate graph y>4x²-12x
asked Jan 19, 2015 in PRECALCULUS by anonymous

1 Answer

0 votes

Step 1:

The inequality is image
Write related equation is image and it is represent parabola curve.

The graph of the inequality image is the shaded region, so every point in the shaded region satisfies the inequality.

The graph of the equation image is the boundary of the region. Since the inequality symbol is >, the boundary is drawn as a dotted curve to show that points on the curve does not satisfy the inequality and the shaded region of the graph of image is the soutions to the inequaity.

Step 2:

Graph the boundary of curve make the table of values to find ordered pairs that satisfy the equation.

Choose random values for image and find the corresponding values for image.

image

image

image

-1

image

(-1, 16)

0

image

(0, 0)

1

image

(1, -8)

2

image

(2, -8)

3

image

(3, 0)

4

image

(4, 16)

 

answered Jan 19, 2015 by david Expert

Step 3:

To graph the inequality image follow the steps.

1. Draw a coordinate plane.

2. Plot the points found in table and draw a smooth curve through these points.

3. To determine Shaded region (out side or in side), use a test point inside the parabola.

A simple choice is image.

Substitute the value of image in the original inequality.

image

image

4. Since the above statement is true, shade the region inside the parabola.

Graph:

.

Related questions

asked Nov 5, 2014 in PRECALCULUS by anonymous
asked Jan 19, 2015 in PRECALCULUS by anonymous
asked Jan 19, 2015 in PRECALCULUS by anonymous
asked Jan 19, 2015 in PRECALCULUS by anonymous
asked Jan 19, 2015 in PRECALCULUS by anonymous
asked Jan 19, 2015 in PRECALCULUS by anonymous
asked Jan 19, 2015 in PRECALCULUS by anonymous
asked Jan 19, 2015 in PRECALCULUS by anonymous
asked Dec 19, 2014 in PRECALCULUS by anonymous
asked Dec 19, 2014 in PRECALCULUS by anonymous
asked Dec 19, 2014 in PRECALCULUS by anonymous
asked Dec 19, 2014 in PRECALCULUS by anonymous
asked Dec 19, 2014 in PRECALCULUS by anonymous
asked Dec 9, 2014 in PRECALCULUS by anonymous
asked Dec 9, 2014 in PRECALCULUS by anonymous
asked Dec 9, 2014 in PRECALCULUS by anonymous
asked Dec 9, 2014 in PRECALCULUS by anonymous
asked Nov 15, 2014 in PRECALCULUS by anonymous
asked Nov 15, 2014 in PRECALCULUS by anonymous
asked Nov 5, 2014 in PRECALCULUS by anonymous
...