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Solve log (2x-2) + log(x-2) = log(x+9)+log(x-1)?

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Solve log (2x-2) + log(x-2) = log(x+9)+log(x-1)?

local-maximum
local-minimum

asked Feb 19, 2015 in CALCULUS by anonymous

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1 Answer

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Step 1 :

The equation is .

Apply product rule of logarithm : .

If , then .

The solutions are an .

Since logarithm of negative numbers does not exist, the solution is

Solution :

The solution is .

answered Feb 20, 2015 by Thomas Apprentice

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