Solve. log x^3 - log2 = log( 2x^2)?

Question

Please show all steps when solving. Thank you!

Answer 1

log x^3 - log2 = log( 2x^2)?

logx³-log2=log2x²

Add log2 to each side

logx³-log2+log2=log2x² +log2

logx³=log2x² +log2

Subtract log2x² from each side.

logx³-log2x²=log2x² +log2-log2x²

logx³-log2x²=log2

3logx-log2x²=log2                                                     logA^M=MlogA

3logx-(log2+logx²)=log2                                         log(AB)=logA+logB

3logx-log2-logx²=log2

3logx-log2-2logx=log2                                            logA^M=MlogA

       Add log2 to each side

3logx-log2-2logx+log2=log2+log2

3logx-2logx=2log2

logx=log2²                                                                MlogA=logA^M

logx=log4

Cacel 'log' terms.

x=2

there fore x=2

Comments

Cancel 'log' terms.

x = 4.

The solution is x = 4.