Welcome :: Homework Help and Answers :: Mathskey.com

Q&A
Unanswered
Categories
Users
Ask a Question

Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

Q&A Categories
BASIC MATH (93)
PRE-ALGEBRA (441)
ALGEBRA 1 (2,220)
GEOMETRY (864)
ALGEBRA 2 (2,751)
TRIGONOMETRY (1,187)
PRECALCULUS (1,903)
CALCULUS (2,802)
STATISTICS (129)
PHYSICS (659)
CHEMISTRY (137)
MECHANICAL ENGINEERING (64)
ELECTRICAL ENGINEERING (207)
Winplot Tutorials (2)

Most popular tags

solving-equations system-of-equations functions math slope-intercept-form physics homework-help trigonometric-identities integration limits substitution-method calculus

13,459 questions

17,854 answers

1,446 comments

807,716 users

2log3^n-log3^2n=2

0 votes

logarithmic functions.

logarithmic-equations
logarithmic-functions

asked Mar 6, 2014 in ALGEBRA 2 by chrisgirl Apprentice

Share this question

Google+ Facebook Twitter LinkedIn Reddit

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 votes

The logarithmic equation is 2 log 3^n - log 3^2n = 2.

Apply power property of logarithm : n log a = log a ^n.

log 3^2n - log 3^2n = 2

0 = 2.

The above statement is false, so the equation has no solution.

answered Mar 28, 2014 by lilly Expert

Please log in or register to add a comment.

Related questions

log3(x + 3) − log3(x − 3) = 2

asked Feb 18, 2014 in ALGEBRA 1 by rockstar Apprentice

logarithmic-equations
solving-equations

logarithmic equations log2x-log(x-7)=log3

asked Dec 6, 2013 in ALGEBRA 2 by rockstar Apprentice

logarithmic-equations

Log3(X-1)+log3(X+3)-log(x+1)=1 find solution?

asked Feb 18, 2014 in ALGEBRA 1 by harvy0496 Apprentice

logarithmic-equations
solving-equations

How do you graph this logarithmic equation by rearranging it y=2log1/2x) the log base is 1/2

asked Nov 21, 2013 in ALGEBRA 2 by dkinz Apprentice

logarithmic-functions

Where do i find the notes for chapter 3 section 2?

asked Dec 8, 2015 in PRECALCULUS by samanthamarks Rookie

logarithmic-functions

log(x+2)-log(x)=3

asked Mar 8, 2014 in ALGEBRA 2 by linda Scholar

logarithmic-equations
solving-equations

solve 2 log7(1-2x)=12

asked Feb 18, 2014 in ALGEBRA 2 by angel12 Scholar

logarithmic-equations
solving-equations

expand the following logarithmic {(4(x-5)^2/x^4(x-1)^3)}

asked Dec 6, 2013 in ALGEBRA 2 by johnkelly Apprentice

logarithmic-equations

Convert 7^x-2=200 to logarithmic

asked Dec 6, 2013 in ALGEBRA 2 by payton Apprentice

logarithmic-equations

3log(x+2)=6 How to solve for x?

asked Jun 27, 2013 in ALGEBRA 2 by angel12 Scholar

logarithmic-equations

Logarithm Problem? Algebra 2? I have a test on this tomorrow!?

asked Jan 9, 2013 in ALGEBRA 2 by angel12 Scholar

logarithmic-equations

Solve. log x^3 - log2 = log( 2x^2)?

asked Jan 8, 2013 in ALGEBRA 2 by linda Scholar

logarithmic-equations

Trigonometry

asked Jun 28, 2016 in TRIGONOMETRY by anonymous

functions
logarithmic-functions
derivatives
derivative

help? -(-derivatives -trig-functions-exponential logs-)

asked May 2, 2015 in CALCULUS by anonymous

derivatives
derivative
functions
logarithmic-functions
equation-of-a-tangent-line

help?-derivatives -trig-functions-exponential logs-

asked May 2, 2015 in CALCULUS by anonymous

derivatives
derivative
functions
differentiation
logarithmic-functions

Exponential and Logarithmic Functions.

asked Jan 22, 2015 in PRECALCULUS by anonymous

domain-range
inverse-functions
asymptotes
logarithmic-functions

logarithmic function help!!!!

asked Dec 10, 2014 in CALCULUS by anonymous

logarithmic-functions

logarithmic function helpppp :(

asked Dec 10, 2014 in CALCULUS by anonymous

logarithmic-functions

log4(x+3)+log4(2-x)=1

asked Feb 18, 2014 in ALGEBRA 1 by futai Scholar

logarithmic-equations
solving-equations

Solve each equation

asked Oct 26, 2018 in ALGEBRA 2 by anonymous

solve-equation
single-variable-equation
logarithmic-equations

Copyright © 2024 MATHSKEY. All Rights Reserved. Sitemap|Terms Of Use|Disclaimer|Contact Us|FAQ

...