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help.

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asked Apr 26, 2015 in CALCULUS by anonymous

5 Answers

0 votes

(6_a)

Find .

The function is .

As tends to image, image become arbitrarily large.

Hence, image approaches to positive large number.

As tends to image, image approaches to positive large number.

image.

Solution :

(6_a) image.

answered Apr 27, 2015 by Lucy Mentor
edited Apr 27, 2015 by Lucy
0 votes

(6-b)

Step 2:

Find image.

The function is .

As tends to image, image become arbitrarily large.

Hence, image approaches to positive large number.

As tends to image, image approaches to positive large number.

image.

Solution :

(6_b) image.

answered Apr 27, 2015 by Lucy Mentor
edited Apr 27, 2015 by Lucy
0 votes

(7_a)

Find .

The function is .

As tends to image, the first term is zero.

As tends to image, second and third terms are large positive in the function.

The overall function approaches to large negative number.

As tends to image, approaches to large negative number.

.

Solution :

.

answered Apr 27, 2015 by Lucy Mentor
edited Apr 27, 2015 by Lucy
0 votes

(7_b)

Find image.

The function is .

As tends to image, the first term is large positive number in the function.

As tends to image, second and third terms are approximately equal to 0 in the function.

The overall function approaches to large positive number.

As tends to image, approaches to large positive number.

.

Solution :

.

answered Apr 27, 2015 by Lucy Mentor
0 votes

(8)

Evaluate image.

As  tends to image, image become arbitrarily large.

image approaches to large positive number.

As  tends to imageimage approaches to large positive number.

image

Solution:

image

answered Apr 27, 2015 by Lucy Mentor

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