help9

Question

Answer 1

Step 1:

(4.3)

The two branches current are A and A.

If the polar form of equation is then complex form of .

Complex form of equation is

Complex form of equation is

For parallel connection : .

Hence the resultant current is .

in polar form can be written as .

Hence

Compare the above equation with .

Here A and

Solution :

Answer 2

Step 1:

(4.4.1)

The two impedance of the circuit are  and .

Voltage applied is 270.825 V.

The two impedance are in parallel : .

The total impedence of the circuit is ohms.

Solution :

The total impedence of the circuit is ohms.

Answer 3

Step 2:

(4.4.2)

Find the current flowing in the circuit.

Current flowing in the circuit is .

Total current flowing in the circuit A.

Solution :

Total current flowing in the circuit A.

Answer 4

Step 1 :

(4.4.3)

Current passes through impedence is .

Current passes through impedence

Current passes through impedence is .

Current passes through impedence is

solution :

Current passes through impedence

Current passes through impedence is

Answer 5

Step 1 :

(4.4.4)

Total current flowing in the circuit is A. (From 4.4.2)

Total applied voltage is .

The total power is .

The total power is

Solution :

The total power is

Answer 6

Step 1 :

(4.4.5)

Find Power Factor.

Total current flowing in the circuit is A. (From 4.4.2)

in polar form can be written as .

Power Factor of the circuit is .

.

Power Factor is 1 lead.

Solution :

Power Factor is 1 lead.