radicals

Question

Answer 1

[ 64 (a^3)(b^6)(c^9) ]^(1/3)   =   [ (4^3) (a^3)(b^2)^3 (c^3)^3 ]^(1/3)

                                             =   [ (4^3)^(1/3)] [(a^3)^(1/3)] [(b^2)^3]^(1/3) [(c^3)^3 ]^(1/3)

[ 64 (a^3)(b^6)(c^9) ]^(1/3)   =   4a(b^2)(c^3)