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How do I find tan (2x)?

0 votes

If sinx=47sinx=47x in quadrant I, then find (without finding x):

sin(2x)

cos(2x)

tan(2x)

asked Feb 28, 2018 in TRIGONOMETRY by anonymous

1 Answer

0 votes

Draw the geometry diagram

sinx= 4/7

cosx=√(33)/7

tanx=4/√(33

sin 2x =2sinxcosx

         = 2 ( 4/7)(√(33)/7)

        = 8√(33)/49

cos 2x = 2cos^2(x) -1

         =2(√(33)/7)^2 -1

         = 2(33/49)-1

          =17/49

Tan2x=sin2x/cos2x=[8√(33)/49]/[17/49] = 8sqrt(33)/17

answered Mar 27, 2018 by johnkelly Apprentice

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