Question

Find the real or imaginary solutions by completing the square x^2 -6x -4= 0

Answer 1

The equation x^2 - 6x - 4  =  0

Separate variables and constants aside by add 1 to each side.

x^2 - 6x  =  4

To change the expression into a perfect square trinomial add (half the x coefficient)² to each side of the expression.

x^2 - 6x + (3)^2   =   4 + (3)^2

(x - 3)^2   =   4 + 9

(x - 3)^2   =   13

Take square root on both sides.

(x - 3)   =   ± √13

x   =   3 ± √13

Solutions are x = 3 + √13 and x = 3 - √13

Answer :

Solutions are x = 3 + √13 and x = 3 - √13.