solve system of equations elimination 6x+4y=42 and -3x+3y=-6

Question

6x+4y=42  and -3x+3y=-6 system of elimination

Answer 1

Elimination method

Given equation 6x+4y = 42 --------> (1)

And -3x+3y = -6

Multiple to each side by 2.

-6x+6y = -12 ---------> (2)

To eliminate the x value add the equations (1) and (2).

6x+4y = 42

-6x+6y = -12

__________

10y = 30

Divide to each side by 10.

10y/10 = 30/10

⇒ y = 3

Substitute the y value in (1).

6x+4*3 = 42

6x+12 = 42

Subtract 12/5 from each side.

6x-12+12 = 42-12

6x = 30

Divide to each side by 6

6x/6 = 30/6

⇒ x =5

Solution x = 5, y = 3.