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using substitution solve for 3x-4y=-2 and -6x+8y=1.

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using substitution solve for 3x-4y=-2 and -6x+8y=1.

system-of-equations
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asked Feb 17, 2014 in ALGEBRA 2 by chrisgirl Apprentice

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1 Answer

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Given equations are 3x-4y = -2 ---> (1)

-6x+8y = 1 --->(2)

Observe the given lines are parallel.

We know that parallel lines are doesnot intersect.

So the given system has no solution.

answered Feb 17, 2014 by friend Mentor

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