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2x-y=0 and 4x-y=2

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solve the following system of equations graphically.

asked Feb 19, 2014 in ALGEBRA 1 by harvy0496 Apprentice

1 Answer

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The first line equation is 2x - y = 0.

Write the equation in slope - intercept form y = mx + b, where m is slope and b is y - intercept.

y = 2x.

Compare the equation with slope - intercept form y = mx + b.

slope = 2 and y - intercept is 0.

y - intercept is 0, so the line crosses the y - axis at origin (0, 0).

Using slope find the next point.

Slope = rise/run = 2/1

Start at point (0, 0), move 2 units up and 1 unit right, then plot the point (1, 2).

Draw a line through these points.

The second line equation is 4x - y  = 2.

Write the equation in slope - intercept form y = mx + b, where m is slope and b is y - intercept.

y = 4x - 2.

Compare the equation with slope - intercept form y = mx + b.

slope = 4 and y -intercept is - 2.

y - intercept is - 2, so the line crosses the y - axis at (0, - 2).

Using slope find the next point.

Slope = rise/run = 4/1

Start at point (0, - 2), move 4 units up and 1 unit right, then plot the point (1, 2).

Draw a line through these points.

Graph :

From the graph lines are intersecting at (1, 2).

So, the solution of the given system is x = 1 and y = 2.

 

answered Aug 27, 2014 by lilly Expert

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