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f(x)=x^2+6x+5 find the x value of the vertex

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f(x)=x^2+6x+5 find the x value of the vertex.

vertex-of-a-parabola

asked Feb 21, 2014 in ALGEBRA 2 by johnkelly Apprentice

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1 Answer

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Given parabola y = x^2+6x+5

Compare it standard parabola form y = ax^2+bx+c

a = 1, b = 6, c = 5.

Axis of symmetry x = -b/2a

x = -6/2

x = -3

x value of the vertex is -3.

answered Feb 21, 2014 by ashokavf Scholar

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