the area of a rectangle is (10x^2+21x+9)cm^2. The length is (5x+3)cm.w is he width

Question

the area of a rectangle is (10x^2+21x+9)cm^2. The length is (5x+3)cm.what is the width.

Answer 1

Rectangle area(A) = l*b

A = (10x^2+21x+9)cm^2, l = 5x+3

10x^2+21x+9 = (5x+3)b

Divide to each side by 5x+3.

b = (10x^2+21x+9)/(5x+3)

5x+3) 10x^2+21x+9 (2x+3

          10x^2+6x

          (-)     (-)

        ________

                    15x+9

                     15x+9

                    (-)    (-)

                   _______

                         0

b = 2x+3

Width of rectangle is 2x+3.