Quotient?? Divisor?

Question

what's the divisor and quotient of this problem?

(3x^3+2x^2-6x+4 )/ (x+1)

Answer 1

Rewrite the expression in long division form (3x³ + 2x² - 6x + 4)/(x + 1).

Divide the first term of the dividend by the first term of the divisor 3x³/x = 3x².

So,the first term of the quotient is 3x². Multiply (x + 1) by 3x² and subtract.

Divide the first term of the last row by first term of the divisor -x²/x = -x.

So,the second term of the quotient is -x. Multiply (x + 1) by (-x) and subtract.

Divide the first term of the last row by first term of the divisor  (- 5x)/x = - 5.

So,the third term of the quotient is (- 5). Multiply (x + 1) by (- 5) and subtract.

The remainder is the last entry in the last row.There fore, R = 9.

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The divisor d(x) = x + 1 and quotient q(x) = 3x² - x - 5.