Math Question!?

Question

DIVIDE: (6x^2+13x-4)/(2x+5)

Answer 1

The expression (6x² + 13x - 4)/(2x + 5)

Divide the first term of the dividend by the first term of the divisor (6x²)/2x = 3x.

So, the first term of the quotient is x³. Multiply (x - 3) by x³ and subtract.

2x + 5) 6x² + 13x - 4 (3x

           6x² + 15x

(-) ______________________

            - 2x - 4         

Divide the first term of the last row by first term of the divisor (- 2x)/(2x) = - 1.

So,the second term of the quotient is - 1. Multiply (2x + 5) by (- 1) and subtract.

2x + 5) 6x² + 13x - 4 (3x - 1

           6x² + 15x

(-) ______________________

            - 2x - 4 

           - 2x - 5

(-) ______________________

                 1

The result of the division is (6x² + 13x - 4)/(2x + 5) = (3x - 1) + 1/(2x + 5).

The result of the division is (6x² + 13x - 4)/(2x + 5) = (3x - 1)(2x + 5) + 1.