Find the orthocenter of triangle ABC with vertices

Question

A(1,-3), B(2,7), C(-2,-3)

Answer 1

Lets find with the points A(1,-3), B(2,7) and C(-2,-3).

Find the slope of the sides AB, BC and CA using the formula y2-y1/x2-x1.

Consider the points of the sides to be x1,y1 and x2,y2 respectively.

Kindly note that the slope is represented by the letter 'm'.

Slope of AB (m) = 7-(-3)/2-1 =10.

Slope of BC (m) = -3-7/-2-2 =10/4.

Slope of CA (m) =- 3+3/-2-1 = 0.

Now, lets calculate the slope of the altitudes AD, BE and CF which are perpendicular to BC, CA and AB respectively. The slope of the altitude = -1/slope of the opposite side in triangle.

Slope of AD = -1/slope of BC = -4/10.

Slope of BE = -1/slope of CA = -1/0.

Slope of CF = -1/slope of AB = -1/10.

Once we find the slope of the perpendicular lines, we have to find the equation of the lines AD, BE and CF.

Lets find the equation of the line AD with points (1,-3) and the slope -4/10.

Formula to find the equation of orthocenter of triangle = y-y1 = m(x-x1)

y+3 = -4/10(x-1)

By solving the above, we get the equation 4x+10y = -26 ---------------------------1

Similarly, we have to find the equation of the lines BE and CF.

Equation for the line BE with points (2,7) and slope -1/0 = y-7 = -1/0(x-2)

By solving the above, we get the equation x = 2          -----------------------------2

Equation for the line CF with points (-2,-3) and slope 1/10 :y+3 =-1/10(x+2)

Find the values of x and y by solving any 2 of the above 3 equations.

In this example, the values of x any y are (2, -34/10) which are the coordinates of the Orthocenter(o).