How do I write an equation in slope-y-intercept of the line

Question

containing the point (2,-5) if it is parallel to the line 2x-6y=18?

Answer 1

Given equation of line , 2x-6y=18

Convert the above line into the form of y = mx+c

6y=2x-18

y=(2/6)x-(18/6)

  =(1/3)x-3

Therefore slope(m) = 1/3

The parallel equation slope is m1=m=1/3

The equation of line parallel to the given equation and passing through (2,-5) is,

=> y-y1=m1(x-x1)

=> y-(-5)=(1/3)(x-2)

=> y+5=(1/3)(x-2)

=> y+5=(1/3)x-(2/3)

=> y=(1/3)x-(2/3)-5

=> y=(1/3)x-17/5

Parallel line equation is y=(1/3)x-17/5