What is the equation for the axis of symmetry of the quadratic function f(x) = 5x^2 + 20x - 16?

Question

I need to find the axis of symmetry for the equation and I don't exactly know the answer.

Answer 1

The quadratic function f (x ) = 5x ^2 + 20x - 16.

The standard form of parabola is y = ax ^2 + bx + c.

Compare the given function with the standard form of parabola y = ax ^2 + bx + c.

a = 5, b = 20, and c = - 16.

Axis of symmetry x = - b/2a.

Substitute the values b = 20 and a = 5.

x = - 20/2 * 5

   = - 20/10

   = - 2.

Therefore, axis of symmetry (x ) = - 2.