Welcome :: Homework Help and Answers :: Mathskey.com
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,459 questions

17,854 answers

1,446 comments

811,143 users

divide the polynomial

0 votes
-26r^4+22r^3-6r^2+5r+9/-2r.
asked Mar 11, 2014 in ALGEBRA 2 by abstain12 Apprentice

1 Answer

0 votes

Rewrite the expression in long division form (- 26r4 + 22r3 - 6r2 + 5r + 9)/(-2r).

Divide the first term of the dividend by the first term of the divisor (- 26r4)/(-2r) = 13r3.

So,the first term of the quotient is 13r3. Multiply (-2r) by 13r3 and subtract.

image

Divide the first term of the last row by first term of the divisor (22r3)/(-2r) = - 11r2.

So,the second term of the quotient is - 11r2. Multiply (- 2r) by - 11r2 and subtract.

image

Divide the first term of the last row by first term of the divisor (-6r2)/(-2r) = 3r.

So,the third term of the quotient is 3r. Multiply (- 2r) by 3r and subtract.

image

Divide the first term of the last row by first term of the divisor (5r)/(-2r) = - 5/2.

So,the fourth term of the quotient is - 5/2. Multiply (- 2r) by (- 5/2) and subtract.

image

The remainder is the last entry in the last row.There fore, R = 9.

The number along the bottom row are the coefficients of the quotient.

The result of the division is (- 26r4 + 22r3 - 6r2 + 5r + 9)/(-2r) = (13r3 - 11r2 + 3r - 5/2) + 9/(- 2r).

The result of the division is (- 26r4 + 22r3 - 6r2 + 5r + 9) = (-2r)(13r3 - 11r2 + 3r - 5/2) + 9.

answered Aug 31, 2014 by casacop Expert

Related questions

...