divide the polynomial

Question

-26r^4+22r^3-6r^2+5r+9/-2r.

Answer 1

Rewrite the expression in long division form (- 26r⁴ + 22r³ - 6r² + 5r + 9)/(-2r).

Divide the first term of the dividend by the first term of the divisor (- 26r⁴)/(-2r) = 13r³.

So,the first term of the quotient is 13r³. Multiply (-2r) by 13r³ and subtract.

Divide the first term of the last row by first term of the divisor (22r³)/(-2r) = - 11r².

So,the second term of the quotient is - 11r². Multiply (- 2r) by - 11r² and subtract.

Divide the first term of the last row by first term of the divisor (-6r²)/(-2r) = 3r.

So,the third term of the quotient is 3r. Multiply (- 2r) by 3r and subtract.

Divide the first term of the last row by first term of the divisor (5r)/(-2r) = - 5/2.

So,the fourth term of the quotient is - 5/2. Multiply (- 2r) by (- 5/2) and subtract.

The remainder is the last entry in the last row.There fore, R = 9.

The number along the bottom row are the coefficients of the quotient.

The result of the division is (- 26r⁴ + 22r³ - 6r² + 5r + 9)/(-2r) = (13r³ - 11r² + 3r - 5/2) + 9/(- 2r).

The result of the division is (- 26r⁴ + 22r³ - 6r² + 5r + 9) = (-2r)(13r³ - 11r² + 3r - 5/2) + 9.