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factor 18x^2-19 xy-2x-12 y^2+3y

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Factor completely.

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asked Mar 11, 2014 in ALGEBRA 1 by dkinz Apprentice

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1 Answer

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Given : 18x^2 - 19xy - 2x - 12y^2 + 3y.

Factor by grouping,

18x^2 - 19xy - 2x - 12y^2 + 3y

= 18x^2 + 8xy - 2x - 27xy - 12y^2 + 3y

= 2x(9x + 4y - 1) - 3y(9x + 4y - 1)

Factor : (9x + 4y - 1)(2x - 3y).

Therefore, the complete factor of 18x^2 - 19xy - 2x - 12y^2 + 3y is (2x - 3y)(9x + 4y - 1).

answered Apr 12, 2014 by lilly Expert

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