Algebra Homework Plz helpppp :) Thx?

Question

1.) Problem solve! 
The width of a rectangle is one-fourth the length. The perimeter of the rectangle is one hundred thirty feet. What is the width of the rectangle? 

52 feet 
13 feet 
26 feet 

2.) The width of a rectangle is 584 feet shorter than five times its length. The perimeter of the rectangle is 512. What is the length of the rectangle? 
140 feet 
116 feet 
18,230 square feet 

3.) The width of a rectangle is one-fifth the length. The perimeter of the rectangle is 30 feet. What is the width of the rectangle? 
2.5 feet 
8 feet 
10 feet 

4.) If the length of a rectangle is 19 feet more than the width. The perimeter of the rectangle is 342 feet. What is the length of the rectangle? 
76 feet 
95 feet 
110 feet 

Answer 1

1) Length of rectangle = x ft

Width of a rectangle = x/4 ft

Perimeter p = 2(l + w) = 130 ft

2(x + x/4) = 130

2x + x/2 = 130

4x + x = 260

5x = 260

x = 260/5 = 52

Width of a rectangle = 52/4 = 13 ft .

Option 2 is correct answer.

2) Length of a rectangle = x ft

Width of the rectangle = (5x - 584) ft

Perimeter p = 2(l + w) = 512 ft

2(x + 5x - 584 ) = 512

2x + 10x - 1168 = 512

12x   = 1680

x = 1680/12

x = 140

Length of a rectangle = 140 ft.

Option 1 is correct answer.

3) Length of a rectangle = x ft

Width of a rectangle = x/5 ft

Perimeter of the rectangle  2(l +w)= 30 ft

2(x+ x/5 )= 30

x + x/5 = 15

5x + x = 75

6x = 75

x = 75/6 = 12.5

Width of a rectangle = x/5 ft = 12.5/5 = 2.5 ft.

Option 1 is correct answer.

4) Width of a rectangle = x ft

Length of a rectangle = x +19 ft

perimeter of the rectangle = 342 ft

2(x + x+ 19) = 342

4x + 38 = 342

4x = 304

x = 76

Length of a rectangle = x +19 ft = 76 +19 = 95ft

Option 2 is correct answer.