Question

 

Solve. 

A.  x/12 = 16/18 

B. 16/6 = x/24

C. A car uses 32 L of gas to travel 450 km. How many liters would be required to drive 800 km ( to the nearest tenth)? 

 

Answer 1

A. The proportion is x /12 = 16/18

Cross product is  18*x  = 16*12

18x  = 192

Divide each side by 18.

18x /18 = 192/18

Solution x  = 10.66

B. The proportion is 16/6 = x /24

Cross product is  16*24 = x *6

6x  = 384

Divide each side by 6.

6x /6 = 384/6

Solution x  = 64

C. Let L represents number of liters

A Car uses 32 L of gas to travel 450 km.

Write a proportion for the problem using rates.

450/32 = 800/L

Cross product is 450*L = 800*32

450L = 25600

Divide each side by 450.

450L/450 = 25600/450

L = 56.88

A car uses 56.9 L petrol wold be reuired to drive 800km.