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Maths question?

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 solve:
square root(4x - 3) + square root(2x +3) = 6    
 
 

 

asked Aug 18, 2014 in ALGEBRA 2 by anonymous

1 Answer

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The equation is √(4x - 3) + √(2x + 3) = 6.

Square on both sides.

[√(4x - 3) + √(2x + 3)] 2 = 62

(4x - 3) + (2x + 3) + 2√(4x - 3)√(2x + 3) = 36

6x + 2√[(4x - 3)(2x + 3)] = 36

3x + √[(4x - 3)(2x + 3)] = 18

√[(4x - 3)(2x + 3)] = 18 - 3x

(4x - 3)(2x + 3) = (18 - 3x)2

8x2 + 6x - 9 = 324 + 9x2 - 108x

x2 - 114x + 333 = 0

x2 - 111x - 3x + 333 = 0

x(x - 111) - 3(x - 111) = 0

(x - 3)(x - 111) = 0

x = 3 or x = 111

The value of x = 111 does not satisfy the original equation.

The solution is 3.

answered Aug 18, 2014 by anonymous
edited Aug 18, 2014

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