Precalculus question?

Question

So, could anyone tell me how to do this question? 
-2x^5+4x^4-x^3-2x^2+3x-5 / (x-3). 

Answer 1

The Expression is .

We make use of long-division method to solve the problem.

Divide the first term of the dividend by the first term of the divisor -2x⁵/x = -2x⁴

So, the first term of the quotient is -2x⁴. Multiply (x-3) by -2x⁴ and subtract

Divide the first term of the dividend by the first term of the divisor -2x⁴/x = -2x³

So, the first term of the quotient is -2x³. Multiply (x-3) by -2x³ and subtract

Divide the first term of the dividend by the first term of the divisor -7x³/x = -7x²

So, the first term of the quotient is -7x². Multiply (x-3) by -7x² and subtract

Divide the first term of the dividend by the first term of the divisor -23x²/x = -23x

So, the first term of the quotient is -23x. Multiply (x-3) by -23x and subtract

Divide the first term of the dividend by the first term of the divisor -66x/x = -66

So, the first term of the quotient is -66. Multiply (x-3) by -66 and subtract

Therefore,

Quotient is

Remainder is -203