How do i factor this quadratic equation?

Question

9y^2+12y-5=0

Answer 1

Find the factors by completing the square 9y^2+12y-5=0 

Separate variables and constants aside by adding 5 from each side 
9y^2+12y = 5 

Here y^2 coefficient is 9, for perfect square make y^2 coefficient 1. 

Divide each side by 9
y^2+4/3y = 5/9 

To change the expression into a perfect square trinomial add (half the y coefficient)² to each side of the expression. 
Here y coefficient = 4/3. So, (half the y coefficient)² = (4/6)^2= 16/36 

Add 16/36 to each side 
y^2+4/3y +16/36 = 5/9 +16/36 
(y + 4/6)^ 2= 1 

Take square root both sides 
(y + 4/6)= ±√1 

Subtract 4/6 to each side

y = -4/6 ± 1

y = -4/6 + 1 , -4/6 - 1 

y = 2/6, -10/6 

y = 1/3, -5/3