Welcome :: Homework Help and Answers :: Mathskey.com
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,459 questions

17,854 answers

1,446 comments

807,705 users

Answer question and show work please?

0 votes
solve the equation foe the interval [0, 2pie]

csc^5x - 4cscx = 0
asked Apr 22, 2013 in ALGEBRA 1 by abstain12 Apprentice

1 Answer

0 votes

csc5x - 4cscx = 0 [0, 2pi]

Take out common term cscx

cscx(csc4x - 4) = 0

cscx = 0 or csc4x - 4 = 0

sinx = ∞ This is wrong

Therefore csc4x = 4

Take fourth root  to each side

cscx = ±√2 at  [0 , 2pi]

sinx = ±(1 / √2)  at [0 , 2pi]

x = pi / 4 , 3pi / 4 , 5pi / 4 , 7pi / 4.

answered Apr 22, 2013 by diane Scholar

Related questions

asked Sep 20, 2014 in ALGEBRA 1 by anonymous
asked May 13, 2014 in TRIGONOMETRY by anonymous
asked Sep 21, 2018 in ALGEBRA 2 by anonymous
...