Welcome :: Homework Help and Answers :: Mathskey.com
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,459 questions

17,854 answers

1,446 comments

805,839 users

Solving systems of equation using elimination?

0 votes
-5x+2y=-10
3x-6y=-18

7x-4y=-3
2x+5y=-7

3x+2y=-2
5x+2y=10

3x-6y=4
-x+2y=-5

thank you for your time and help. I do not understand these at all
asked May 6, 2013 in ALGEBRA 2 by linda Scholar

4 Answers

0 votes

Elimination method  :

7x - 4y = -3    -(1)

2x + 5y = -7   -(2)

Multiply each side by 5 to the equation (1) and Multiply each side by 4 to the equation (2)

35x - 20y = -15 (3)and

8x + 20y = -28  (4)

Add (3) and (4)

43x = -43

x = -1

Multiply each side by 2 to the equation (1) and Multiply each side by 7 to the equation (2)

14x - 8y = -6       -(5)

14x + 35y = -49   -(6)

Subtract (5) from (6)

-43y = 43

y = -1

 

 

 

 

 

 

 

answered May 6, 2013 by diane Scholar
0 votes

Elimination method  :

-5x + 2y = -10    -(1)

3x - 6y = -18      -(2)

Multiply each side by 3 to the equation (1) and Multiply each side by 5 to the equation (2)

-15x + 6y = -30   (3) and

15x - 30y = -90   (4)

Add (3) and (4)

-24y = -120

y = 5

Multiply each side by 6 to the equation (1) and Multiply each side by 2 to the equation (2)

-30x +12y = -60       -(5)

6x - 12y = -36   -(6)

Add  (5)  to (6)

-24x = -96

x = 4.

answered May 6, 2013 by diane Scholar
0 votes

Elimination method  :

3x + 2y = -2    -(1)

5x + 2y = 10   -(2)

Multiply each side by 5 to the equation (1) and Multiply each side by 3 to the equation (2)

15x +10y = -10   (3) and

15x + 6y = 30   (4)

Subtract  (4) from  (3)

4y = -40

y = -10

Subtract (2) from (1)

-2x = -12

x = 6.

answered May 6, 2013 by diane Scholar
0 votes

Elimination method  :

3x - 6y = 4          -(1)

-x + 2y = - 5      -(2)

The two equation slopes are equal and

The equation (1) and the equation (2) are parallel

So they have no solution.

answered May 6, 2013 by diane Scholar

Related questions

asked Jul 24, 2014 in ALGEBRA 2 by anonymous
...