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Write the expression below as a single logarithm. Please show all of your work.

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asked Jun 19, 2013 in GEOMETRY by futai Scholar

1 Answer

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2 ln(x+ 4) -ln{(x^2 + x - 12)/x}

Formula : a ln(x) = ln(x)

= ln(x + 4)^2 - ln{(x^2 + x - 12)/x}

multiple value form : ln(a) - ln(b) = ln(a/b)

= ln[(x+4)^2 /{(x^2 + x - 12)/x}]

= ln[(x(x+4)^2) /(x^2 + x - 12)]

Formula :(a + b)^2 = a^2 +2ab +b^2

= ln[(x(x^2 + 8x +16) /(x^2 + x - 12)]

= ln[(x^3 +8x^2 +16x) /(x^2 + x - 12)]

The solution is = ln[(x^3 +8x^2 +16x) /(x^2 + x - 12)]

 

answered Jun 19, 2013 by anonymous

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