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olve the system of equations below.

y=x^2+3x+2 and y = x+2

asked Sep 5, 2018 in ALGEBRA 2 by futai Scholar
reshown Sep 5, 2018 by bradely

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1 Answer

The system of equations

y = x^2 + 3x + 2 -------------> (1)

y = x + 2 -------------------> (2)

Substitute y = x + 2 in Eq (1)

x + 2 = x^2 + 3x + 2

x^2 + 3x + 2 - (x + 2) = 0

x^2 + 3x + 2 - x - 2 = 0

x^2 + 2x = 0

x(x + 2) = 0

x = 0 ; (x + 2) = 0

x = 0 ; x = - 2

Answer :

The Solutions are x = 0, x = - 2.

answered Sep 28, 2018 by homeworkhelp Mentor

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