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Find the exponential function f(x)=Ca^x whose point is (2,2/9)

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asked Sep 26, 2018 in PRECALCULUS by anonymous

1 Answer

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The functioon is f(x)  =  Ca^x

The point is (2, 2/9)

Substitute the point (x, f(x)) = (2, 2/9) in f(x)

2/9  =  Ca^2

C  =  2/(9a^2)

Substitute  C  =  2/(9a^2) in f(x)

f(x) = [ 2/(9a^2) ]a^x

f(x) = (2/9)[ a^(x - 2) ]

Answer :

f(x) = (2/9)[ a^(x - 2) ]

answered Nov 7, 2018 by homeworkhelp Mentor

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