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factor the expression completly

0 votes
6x^3-4x^2-16x
asked Oct 14, 2018 in ALGEBRA 2 by anonymous

1 Answer

0 votes

6x^3 - 4x^2 - 16x  =   2x(3x^2 - 2x - 8)  

                                 =   2x(3x^2 - 2x - 8)  

                                 =   2x(3x^2 - 6x + 4x - 8)  

                                 =   2x [ (3x(x - 2) + 4(x - 2) ]

                                 =   2x(x - 2)(3x+ 4)

Answer :

6x^3 - 4x^2 - 16x  =  2x(x - 2)(3x+ 4).

answered Oct 14, 2018 by homeworkhelp Mentor

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