Factor completely

Question

2x^3+3x^2-2x-3 or is it not factorable?

 

Answer 1

The expression is 2x³ + 3x² - 2x - 3.

= x² (2x + 3) - 1(2x + 3)

= (x² - 1) (2x + 3)

= (x² - 1²) (2x + 3)                            [Since a² - b² = (a + b)(a - b)]

= (x + 1) (x - 1) (2x + 3) is the solution.