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Factor completely.

0 votes

15u^6- 21u^5- 18u^4.?

factorization

asked Jul 15, 2014 in ALGEBRA 1 by anonymous

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1 Answer

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The expression is 15u⁶ - 21u⁵ - 18u⁴ .

Common out 3u⁴ from the expression.

= 3u⁴ (5u² - 7u - 6)

Factor 5u² - 7u - 6 by factor by grouping.

= 3u⁴ (5u² - 10u + 3u - 6)

= 3u⁴ (5u(u - 2) + 3(u - 2))

= 3u⁴ ((u - 2)(5u + 3)).

∴ 15u⁶ - 21u⁵ - 18u⁴ = 3u⁴ ((u - 2)(5u + 3)).

answered Jul 15, 2014 by lilly Expert

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