solve the equation!!!!!!!!!!!!!!!!!!!!!!!!!!!

Question

Answer 1

Given equation is 4/x + x/(x + 3) = 9/(x^2 + 3x)

                    => [4(x + 3) + x(x)] / x(x + 3) = 9 / (x^2 + 3x)   [By taking LCM]

                    => (4x + 12 + x^2) / (x^2 + 3x) = 9 / (x^2 + 3x)

                    => 4x + 12 + x^2 = 9

                    => x^2 + 4x + 3 = 0

                    => x^2 + x + 3x + 3 = 0

                    => x(x + 1) + 3(x + 1) = 0

                    => (x + 1)(x + 3) = 0

                    => x + 1 = 0, x + 3 = 0

                    => x = -1, x = -3

                    => x = -1, -3

Therefore x = -1, -3.