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Simplify -rationalizing the denominator.

0 votes

(5√2)/(2-i) by rationalizing the denominator.

asked Aug 7, 2013 in ALGEBRA 2 by angel12 Scholar

2 Answers

0 votes

Given 5sqrt(2)/(2-i)

Multiply numerator and denominator with (2+i)

= (5sqrt(2)*(2+i))/((2-i)(2+i))

Recall : (a+b)*(a-b) = a^2-b^2

= (5sqrt(2)*(2+i))/(2^2-i^2)

= 5sqrt(2)*2+5sqrt(2)*i)/(4-i^2)         { since i^2 = -1 }

= 10sqrt(2)+5sqrt(2)i/(4+1)

=  10sqrt(2)+5sqrt(2)i/5

Taking 5 common from numerator

= 5(2sqrt(2)+1*sqrt(2)i)/5

= 2sqrt(2)+isqrt(2)

answered Aug 8, 2013 by jeevitha Novice
0 votes

Given that

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Rationalize the denominator

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Take common 5 from numerator and denominator

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answered Aug 8, 2013 by jouis Apprentice

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