solve for z please help||||||||||||||

Question

-3a(4z+4x)-2(5a-4z)=-7ax

Answer 1

-3a(4z+4x)-2(5a-4z)=-7ax

-3a(4z+4x)-2(5a-4z)=-7ax

-12az-12ax-10a+8z=-7ax

each side adding '7ax'

-12az-12ax-10a+8z+7ax=-7ax+7ax

-12az-5ax-10a+8z=0

-12az+8z-5ax-10a=0

z(-12a+8)-5a(x-2)=0

each side adding 5a(x-2)

z(-12a+8)-5a(x-2)+5a(x-2)=0+5a(x-2)

z(-12a+8) =5a(x-2)

each side dividedby (-12a+8)

z(-12a+8)/(-12a+8)=5a(x-2)/(-12a+8)

z=5a(x-2)/(8-12a)

 

           there fore    z=5a(x-2)/(8-12a)

Comments

Therefore  value of z is .