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Solve dividing with polynomials

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2x^9 - 12x^7 + 16x^3/ -2x^6

 

 

asked Nov 19, 2013 in PRE-ALGEBRA by rockstar Apprentice

1 Answer

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Given polynomial is 2x^9-12x^7+16x^3/-2x^6

= 2x^9/-2x^6-12x^7/-2x^6+16x^3/-2x^6

= -x^3+6x-8/x^3

 2x^9-12x^7+16x^3/-2x^6 =    -x^3+6x-8/x^3     

answered Dec 18, 2013 by dozey Mentor

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