Help with polynomials

Question

(x^4+5x^3+6x^2-x-2)/(x+2)?

Answer 1

The expression is

Divide the first term of the dividend by the first term of the divisor x⁴/x = x³.

So,the first term of the quotient is x³. Multiply (x + 2) by x³ and subtract.

Divide the first term of the last row by first term of the divisor 3x³/x = 3x².

So,the second term of the quotient is 3x². Multiply (x + 2) by 3x² and subtract.

 

Divide the first term of the last row by first term of the divisor  (- x)/x = - 1.

So,the third term of the quotient is (- 1). Multiply (x + 2) by (- 1) and subtract.

 

The remainder is the last entry in the last row.There fore, R = 0.

The number along the bottom row are the coefficients of the quotient.

The result of the division is (x⁴ + 5x³+ 6x² - x - 2)/(x + 2) = (x³ + 3x² - 1) + 0/(x + 2).

The result of the division is x⁴ + 5x³+ 6x² - x - 2 = (x + 2)(x³ + 3x²  - 1) + 0.