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Suppose H(t)=√(3t+2) What is the average rate of change of

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Suppose H(t)=√(3t+2) What is the average rate of change of H(t) with respect to t as t changes from 2 to 2.01 ?

average-rate-of-change

asked Nov 23, 2013 in CALCULUS by linda Scholar

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1 Answer

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Given H(t) = √(3t+2)

H(2) = √(3*2+2)

= √8

= 2.82

H(2.01) = √(3*2.01+2)

= √6.03+2

= √8.03

= 2.833

Formula for average rate of change = [f(b)-f(a)]/[b-a]

Average rate of change = [H(2.01)-H(2)]/[2.01-2]

= (2.833-2.82)/0.01

= 0.013/0.01

= 1.3

answered Jan 22, 2014 by dozey Mentor

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