solve the linear system

Question

X+y=1, 3x-y=2

Answer 1

x+y = 1

Subtract y from each side.

x+y-y = 1-y

x = 1-y -------> (1)

3x-y = 2 ----------> (2)

From equation (1) substitute the x value in equation (2).

3(1-y)-y = 2

3-3y-y = 2

3-4y = 2

Subtract 3 from each side.

3-4y-3 = 2-3

-4y  = -1

Divide to each side by negitive 4.

-4y/-4 = -1/-4

y = 1/4

Substitute the y value in equation (1).

x+1/4 = 1

Subtract 1/4 from each side.

x+1/4-1/4 = 1-1/4

x = 3/4

Solution of given equations is x = 3/4 and y = 1/4.