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5(4+2x)-(8x-12)=68

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how do you solve 5(4+2x)-(8x-12)=68

asked Dec 6, 2013 in PRE-ALGEBRA by homeworkhelp Mentor
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1 Answer

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5(4+2x)-(8x-12) = 68

20+10x-8x+12 = 68

32+2x = 68

Subtract 32 from each side.

32-32+2x = 68-32

2x = 36

Divide to each side by 2.

2x/2 = 36/2

x = 18

Solution x = 18.

answered Dec 6, 2013 by william Mentor

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