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12x^2=20x+16x

0 votes

solve over complex numbers

complex-numbers

asked Dec 7, 2013 in ALGEBRA 1 by mathgirl Apprentice

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1 Answer

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12x^2 = 20x+16x

12x^2 = 36x

Subtract 36x from each side.

12x^2-36x = 36x-36x

12x^2-36x = 0

12x(x-3) = 0

12x = 0, x-3 = 0

x = 0, x = 3.

answered Dec 10, 2013 by william Mentor

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