WHAT IS THE VERTEX OF Y=5X^2+10X+24?

Question

WHAT IS THE VERTEX?

Answer 1

Given parabola y = 5x^2+10x+24

Compare it standard parabola form y = ax^2+bx+c

a = 5, b = 10, c = 24.

Axis of symmetry x = -b/2a = -10/10

x = -1

To find vertex substitute x value in given equation.

y = 5(-1)^2+10(-1)+24

y = 5-10+24

y = 19

Vertex of given parabola = (-1,19).