Find 2 consecutive numbers with a product of 121?

Question

what is the answere of the 121 one though?

Answer 1

Let the first number = x

Then it's consecutive number = x  + 1

Product of two consecutive numbers is 121.

x (x  + 1) = 121

x ^2 + x = 121

x ^2 + x - 121 = 0

Compare it to quadratic form ax ^2 + bx + c = 0

a  = 1 , b  = 1, c = -121.

The roots are one must be positive and one must be negitive.

Since the product of  two positive numbers and  negitive numbers  is positive.

If x  = 10.51

The consecutive numbers are 10.51 and 11.51.

If x  = -11.51

The consecutive numbers are -11.51 and -10.51.